Two events E and F are independent if and only if

- P(EF) = P(E) P(F).

Here,

- E = event that the red die is a 1; P(E) = 1/6

F = event that the sum is even; P(F) = 1/2

EF = event that the red die is a 1 and the sum is even; P(EF) = 3/36

(since there are a total of 3 outcomes of this form: (1, 1), (1, 3), and (1, 5) )

Since

1 6 |
1 2 |
= | 3 36 |
, |

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