The volume of $a$ cone of height $h$ and radius of base $r$ is
If $r$ is in error by $±Δr,$ then $V$ is in error by
$ΔV \approx \frac{dV}{dr} Δr$
$ = \frac{2}{3} πr hΔr$
$ = \frac{2}{3} π(2)(10)(0.15) \approx \color{blue}{6.2832} mm^3$
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