Answer for Exercise 5c

In part (b) we obtained the following sampling distribution:

Its expected value is E() = 0(1/9) + (.5)(2/9) + (1)(1/9) + (2.5)(2/9) + (3)(2/9) + 5(1/9) = 18/9 = 2.

Since this is the same as the expected value of X, it follows that is an unbiased estimator of .

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