 |  | t /2 |    n |
Since n = 16 in this example, we use the small sample formula for confidence intervals:
| | t/2 | n |
Here, = 7.3, n = 16, t/2 = t.025 = 2.131, s = 0.3, so we get a confidence interval of
| 7.3 | | 2.131 | 16 |
||
| = | 7.3 | |
0.159825. | ||
This gives an interval of [7.1402, 7.4598]. Notice that if we round these numbers to 2 decimal places, we see that the claimed spiciness of 7.5 just falls in the interval, so the company is (borderline) accurate in its claim.
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