Since n = 16 in this example, we use the small sample formula for confidence intervals:

t_{/2} | n |

Here, = 7.3, n = 16, t_{/2} = t_{.025} = 2.131, s = 0.3, so we get a confidence interval of

7.3 | 2.131 | 16 |
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= | 7.3 | 0.159825. |

This gives an interval of [7.1402, 7.4598]. Notice that if we round these numbers to 2 decimal places, we see that the claimed spiciness of 7.5 just falls in the interval, so the company is (borderline) accurate in its claim.

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