We start by quoting the quotient rule:
d
dx
f
(
x
)
g
(
x
)
=
f
'
(
x
)
g
(
x
)
-
f
(
x
)
g
'
(
x
)
[
g
(
x
)]
2
d
dx
x
2
+ 3
x
+ 2
x
-
1
=
(2
x
+ 3)
(
x
-
1)
-
(
x
2
+ 3
x
+ 2)
(1)
(
x
-
1)
2
=
2
x
2
+
x
-
3
-
x
2
-
3
x
-
2
x
2
-
2
x
+1
=
x
2
-
2
x
-
5
x
2
-
2
x
+1
.
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