The Calculator Thought Experiment (CTE) tells us that the expression
dx |
[(x2 - 1)3(3x + 4)-1] |
= | dx |
(x2 - 1)3 | (3x + 4)-1 | + | (x2 - 1)3 | dx |
(3x + 4)-1 |
= | (3)(2x)(x2 - 1)2(3x + 4)-1 + (x2 - 1)3(-1)(3)(3x + 4)-2 | |
= | 6x(x2 - 1)2(3x+4)-1 - 3(x2 - 1)3(3x+4)-2 |
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