Here is a similar problem worked out for you:
dx |
[(x2 - 1)(3x + 4)-1] |
The Calculator Thought Experiment (CTE) tells us that the expression
dx |
[(x2 - 1)(3x + 4)-1] |
= | dx |
(x2 - 1) | (3x + 4)-1 | + | (x2 - 1) | dx |
(3x + 4)-1 |
= | (2x)(3x + 4)-1 + (x2 - 1)(-1)(3x + 4)-2(3) | |
= | 2x(3x+4)-1 - 3(x2 - 1)(3x+4)-2 |
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