Here is a similar, but not identical problem done out for you:
Suppose the given expression was
\frac{1}{6x} + \frac{x}{6} + \frac{5}{4x^{-2}}
"Exponential form" means that each summand must be in the form Ax^n,
where A and n are constants.
The first term is
\frac{1}{6x} = \frac{1}{6}.\frac{1}{x} = \frac{1}{6}x^{-1}, which has the desired form Ax^n,
The second expression is almost in exponential form already:
\frac{x}{6} = \frac{1}{6}x
The third term is:
\frac{5}{4x^{-2}} = \frac{5}{4}\frac{1}{x^{-2}} = \frac{5}{4}x^2
Putting them together gives
\frac{1}{6}x^{-1} + \frac{1}{6}x + \frac{5}{4}x^2
Now do the similar problem you were given.
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