First, rewrite the integrand in exponent form (it is almost identical to the last quiz item):

7ex

+

1 6x

+

x 6

5 4x2

=

7ex

+

x1 6

+

x 6

5x2 4

( 7ex + 1 6x + x 6 5 4x2 ) dx	=	( 7ex + x1 6 + x 6 5x2 4 ) dx
	=	7ex + ln |x| 6 + x2 12 5x3 12 + C.

In computer/calculator input notation, we can write this in one of several ways, among which are the following:

7e^x + (ln (abs(x)) )/6 + x^2/12 - 5x^3/12 + C
or
7e^x + (1/6)*ln (abs(x)) + x^2/12 - 5x^3/12 + C
or
7e^x + (1/6)*ln (abs(x)) + (1/12)*x^2 - (5/12)*x^3 + C

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