We have

3 2 xu1/2 du	=	3 2 u+1 2 u1/2 du	(substituting for x)
	=	3 4 u3/2+u1/2 du	(simplifying)
	=	3 10 u5/2 + 1 2 u3/2 + C	(taking the antiderivative)
	=	3 10 (2x-1)5/2 + 1 2 (2x-1)3/2 + C	(substituting for u)

You can enter this in any valid format, such as

.3*(2x-1)^2.5 + .5*(2x-1)^1.5 + C

3*(2x-1)^(5/2) /10 + (2x-1)^(3/2) /2 + C

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