Since

u	=	2x2-2x+5
and
dx	=	1 2(2x-1)	du,

	2x-1 (2x2-2x+5)3	dx	=	2x-1 u3 1 2(2x-1) du
			=	1 2u3 du     canceling the term (2x-1)

You can enter this as

du/(2u^3)

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