We have

	1 2u3	du	=	1 2 u3 du	(integrand in exponent form)
			=	1 2 u3 du	(slip the constant outside)
			=	1 2 u2 -2 + C	(evaluate the integral)
			=	- 1 4u2 + C	(simplify)
			=	- 1 4(2x2-2x+5)2 + C	(substitute back)

You can enter this as

-1/(4*(2x^2-2x+5)^2) + C or -(1/4)*(2x^2-2x+5)^(-2) + C

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