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We have

u = x² + 2x - 4

du

dx

=

2x + 2 = 2(x+1)

dx

=

du

2(x+1)

x = 0 ⇒ u = -4
x = 1 ⇒ u = -1

So,

1

0

x + 1

e^{x² + 2x-4}

dx

=

-1

-4

x + 1

e^u

du

2(x+1)

=

-1

-4

1

e^u

du

2

We canceled the term (1+x)

=

1

2

-1

-4

e^-u

du

We wrote 1/e^u as e^-u

(Choice F).

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