P(A) = P((1, 4), (2, 3), (3, 2), (4, 1)) = 4/36 = 1/9
P(B) = P((1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6) ) = 6/36 = 1/6
P(AB) = P(sum is 5 and both the same) = P(impossible event) = 0
Test for Independence
P(AB) | = | P(A)P(B) | ? | ||
= | 9 | . | 6 |
Therefore, the events are not independent.
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