P(A) = P((1, 3), (2, 2), (3, 1)) = 3/36 = 1/12
P(B) = P((1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)) = 6/36 = 1/6
P(AB) = P(sum is 4 and both numbers the same) = P((2, 2)) = 1/36
Test for Independence
P(AB) | = | P(A)P(B) | ? | |||
| = | 12 | . | 6 |
Therefore, the events are dependent.
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