P(A) = P((1, 5), (2, 4), (3, 3), (4, 2), (5, 1)) = 5/36
P(B) = 1/2
P(AB) = P(sum is 6 and the red die is even) = P((2, 4) , (4, 2)) = 2/36 = 1/18
Test for Independence
P(AB) | = | P(A)P(B) | ? | |||
| = | 2 | . | 18 |
Therefore, the events are dependent.
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