Let $f(x) = %0$. Use the definition of the derivative to calculate $f'(%1)$ algebraically as follows:

$f(%1) = {}$
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$f(%1+h) = {}$
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$f(%1+h) = {}$
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Expanded and simplified
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$f(%1+h) - f(%1) = {}$
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Simplified
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$\displaystyle \frac{f(%1+h) - f(%1)}{h} = {}$
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$f'(%1) = {}$
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RANDOMIZE